A capacitor of capacity 1µF is connected in a closed series circuit with a resistance of 10 7 ohms, an open key and a cell of 2 V with negligible internal resistance:
(i) When the key is switched on at time t = 0, find;
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
[(i) 10 s, 2 µC, 10 ln2 = 6.93 sec.,
(ii) q = (2 e –5 ) µC = 1.348 x 10 -8 C]
Sol. (i) Time constant = t = RC = 10 7 × 1 × 10 –6
= 10 sec.
Q 0 = CV = 1 × 10 –6 × 2 = 2 µC
Q = 
= Q 0 (1 – e –t/Rc )
= ln2
⇒ t = 10 ln2 = 6.93 sec.
(ii) q = q 0 e –t/RC
= 2 × 10 –6 e –50/10 = 2 × 10 –6 e –5 = 1.348 × 10 –8 C.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
The capacity of a parallel plate condenser is . When a glass plate is placed between the plates of…
A capacitor is charged by using a battery which is then disconnected. A dielectric slab is then sli…
The energy of a charged capacitor is given by the expression ( = charge on the conductor and C = i…
The capacity of a condenser is farad and its potential is . The energy released on discharging it…
The insulated spheres of radii and having charges and respectively are connected to each other.…
In a charged capacitor, the energy resides